GHARIB Posted June 16, 2020 Share Posted June 16, 2020 2 1 Quote Link to comment Share on other sites More sharing options...
Sasirou Posted June 16, 2020 Share Posted June 16, 2020 This a and b is convicing, i watched the 0 = 1 prof and wasnt so conviced as this one 😮 1 2 Quote Link to comment Share on other sites More sharing options...
ChaOs Posted June 16, 2020 Share Posted June 16, 2020 If Swiss cheese has holes and more cheese means more holes and more holes means less cheese, then does more cheese mean less cheese? 4 Quote Link to comment Share on other sites More sharing options...
ChaOs Posted June 16, 2020 Share Posted June 16, 2020 48 minutes ago, GHARIB said: 1 = 1 1² = 1*1 1² - 1² = 1*1 - 1² (1+1) * (1-1) != 1 * (1-1) And he don't sho at the end of line, what he calculates. for example line 1: 1 = 1 | ^2 1 2 Quote Link to comment Share on other sites More sharing options...
Sasirou Posted June 16, 2020 Share Posted June 16, 2020 Just now, ChaOs said: If Swiss cheese has holes and more cheese means more holes and more holes means less cheese, then does more cheese mean less cheese? Swiss Cheese = Holes Lets multiple with more 😛 More S.Cheese = More holes (1) And we know that More Holes = Less cheese (2) Then we can conclude 😛 from 1 and 2 : More S.Cheese = Less Cheese 1 1 1 Quote Link to comment Share on other sites More sharing options...
GHARIB Posted June 16, 2020 Author Share Posted June 16, 2020 3 minutes ago, ChaOs said: 1 = 1 1² = 1*1 1² - 1² = 1*1 - 1² (1+1) * (1-1) != 1 * (1-1) And he don't sho at the end of line, what he calculates. for example line 1: 1 = 1 | ^2 You get it ! 1 1 Quote Link to comment Share on other sites More sharing options...
ElEl Posted June 16, 2020 Share Posted June 16, 2020 16 minutes ago, ChaOs said: (1+1) * (1-1) != 1 * (1-1) This isn't true. (1+1)*(1-1) does equal 1*(1-1) because both sides equal 0 (2 lots of 0 is equal to 1 lot of 0). This works for any value of a. The problem with the proof is he divided both sides by (1-1) i.e. 0 which is a big no-no in maths. The entire "proof" up until the point he divided by (1-1) is accurate. 4 Quote Link to comment Share on other sites More sharing options...
ChaOs Posted June 16, 2020 Share Posted June 16, 2020 2 minutes ago, ElEl said: (1+1)*(1-1) does equal 1*(1-1) It doesn't. Mathemathically yes. But not in informatic. This is forbidden to take zero values out of the blue. a=7, b=6 7*0 = 6*0 a=b. Well done, sorcerer. Quote Link to comment Share on other sites More sharing options...
ElEl Posted June 16, 2020 Share Posted June 16, 2020 Just now, ChaOs said: It doesn't. Mathemathically yes. But not in informatic. This is forbidden to take zero values out of the blue. a=7, b=6 7*0 = 6*0 a=b. Well done, sorcerer. You've just made the exact mistake the proof has in the video. The same mistake I highlighted in my previous post. You've divided both sides by zero to get to a=b. 🤦♂️ If you'd like to expand on your mistake, feel free. I've got a degree in mathematics so I'd be happy to shoot it down again. Well done. 1 1 Quote Link to comment Share on other sites More sharing options...
Cocanation Posted June 16, 2020 Share Posted June 16, 2020 I love this videos! I had seen few years ago xD. The teacher explain the errors on the videos 1 Quote Link to comment Share on other sites More sharing options...
ChaOs Posted June 16, 2020 Share Posted June 16, 2020 A mistake to show sth. of. You really think, I am stupid. Isn't it? I often had as informatic discussions with mathemathics. Everytime the same about the word "equal". In IT (1+1) * (1-1) does NOT equal 1 * (1-1) because of obvious reasons. Quote Link to comment Share on other sites More sharing options...
ElEl Posted June 16, 2020 Share Posted June 16, 2020 2 minutes ago, ChaOs said: In IT (1+1) * (1-1) does NOT equal 1 * (1-1) because of obvious reasons. It does though. Put both sides into a calculator and you'll get the same result. Times any number by 0 and it will become 0. Why is this so hard for you to understand? Let me go through the steps for you: (1+1) * (1-1) = (2) * (0) = 0 1 * (1-1) = 1 * (0) = 0 OH DAMN. We have equality of both sides of the equation. Thus: (1+1) * (1-1) = 1 * (1-1). Explain these "obvious reasons" cause clearly I'm the stupid one here. 1 Quote Link to comment Share on other sites More sharing options...
ChaOs Posted June 16, 2020 Share Posted June 16, 2020 (edited) because 1+1 is not equal to 1, so (1+1)*0 and 1*0 is also not equal, even when the same result comes out. The latest point of clarification can deliver any program language that would kick you out this direct line, when you logic like that. Again. Each value times zero is zero. That make not the values equal. Instead it shows the same result. Edited June 16, 2020 by ChaOs 1 Quote Link to comment Share on other sites More sharing options...
ElEl Posted June 16, 2020 Share Posted June 16, 2020 2 minutes ago, ChaOs said: Again. Each value times zero is zero. That make not the values equal. Instead it shows the same result. Yes this is the mistake that the video made. Your mistake is a different one. 2 minutes ago, ChaOs said: because 1+1 is not equal to 1, so 1+1*0 and 1*0 is also not equal, even when the sam result cames out. I think you need to learn about brackets and why what you've just said is completely irrelevant to the point at hand. You can't just choose what brackets to look at in this case because then you're dividing by what you're choosing not to look at. You're dividing by 0.. again. I don't have the energy to explain basic maths anymore. 1 1 Quote Link to comment Share on other sites More sharing options...
GHARIB Posted June 16, 2020 Author Share Posted June 16, 2020 (edited) 2 hours ago, ElEl said: This isn't true. 2 hours ago, ChaOs said: because 1+1 is not equal to 1, so 1+1*0 and 1*0 is also not equal, even when the same result comes out. You can not simplify A-B because it is equal to 0... You can not divide by 0. This is the error. Edited June 16, 2020 by GHARIB 1 1 Quote Link to comment Share on other sites More sharing options...
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