ugh.. you lost me. And I'm kind of good with math... is this supposed to be funny?

lol no i just had spare time to waste before whatever i wanted to watch on telly come Which part you lost on? I actually manged to learn this myself from some website a long time ago. Havent done it in ages but can work it out

lol wait you can use this

http://www.hellam.net/algebra/simul1.html

its great

Ok look at

http://www.bbc.co.uk/schools/gcsebitesize/maths/algebra/simultaneoushirev1.shtml

_______________________________________________________________________________________

Its probaley clearer on the link but....

  Quote

Solve these simultaneous equations and find the values of x and y.

 

* Equation 1: 2x + y = 7

* Equation 2: 3x - y = 8

As you can see they are already in the format ax +by = c

And also the Y coefficent is already matched up. Since the two coeffiecentsa are different you need to add

  Quote

Add the two equations to eliminate the ys:

 

* 2x + y = 7

* 3x - y = 8

* ------------

* 5x = 15

* x = 3

Now you got x =3, put into equation 1 (as i state in the guide above, not in the link. its the same results either way but i like to double check)

Equation 1 ) 2x + y = 7

2 x 3 + y = 7

6 + y = 7

y=1

Equation 2 ) 3x - y = 8

3 x 3 - 1 = 8

It works so

X = 3, Y =1

Scroll to the bottom an you 'll see they havent arranged

  Quote

Equation 1: y - 2x = 1

 

Equation 2: 2y - 3x = 5

Into the ax +by = c format but you can

  Quote

Equation 1: -2x +y = 1

 

Equation 2: -3x +2y = 5

Now if we multipoly equation 1 by 2 to make coefficent of Y to match up

  Quote

Equation 1: -4x +2y = 2

 

Equation 2: -3x +2y = 5

This comes to

  Quote

-x = -3

 

means

  Quote

x =3

aubstitue into equation 1

  Quote

Equation 1: 2 x 3 +y = 1

means

  Quote

6 + y = 1

rearange to

  Quote

6 + 1 = y

  Quote

y = 7

  Quote

 

Equation 2: -3x +2y = 5

to check this is correct put both y and x into equation 2

  Quote

 

Equation 2: -3 x 2 +2 x 7 = 5

x = 3 , y =7 . same results as the link

(lol sorry ran out of the number of quotes im allowed )

Lol i was only ever good on this part of the course ^^ Hopeless at the graphs/quadractic's

OMFG .... I always hate math... blehhh

  Baska (PL) said:

OMFG .... I always hate math... blehhh

I loved maths so much i took sn A lelvel in it even though i got all Us in my exams

Oops Sorry i thought I'm still in f|a forum for games... OK got it so my browser didn't clean old forum cache I visited last time by accident and talking about math

ROFL F25, i was sittin in math today, totally stuck on this, and i whipped out my laptop and started browsing the forums. Stumbled upon this gem, and now i understand!!!

God bless you =F|A= Priest

  -=Medic=- said:

Oops Sorry i thought I'm still in f|a forum for games... OK got it so my browser didn't clean old forum cache I visited last time by accident and talking about math

lol well...maths can be fun And rofl val. Hope this works - dont blame me if it dosent, blame the BBC

O_O what the hell xD this is so simple solved in an other way xD

2x = 6 - 4y

-3 - 3y = 4x

take first equation and fint the x --> x = 3 - 2y

then substitute in the other equation --> - 3 - 3y = 12 - 8y

solve --> 5y = 15 --> y = 3

substitute in first equation --> 2x = -6 --> x = -3

and that's done

i use that method only when i 've got to do whith harder equations, like in analytic geometry when u gotta find common points between two circumferences or parables like this:

x^2 + y^2 + 5x + 6y + 13

x^2 + y^2 + 12x + 7y + 2

in that way u can get rid of squared terms and find x & y

  Nik00 said:

O_O what the hell xD this is so simple solved in an other way xD

 

2x = 6 - 4y

-3 - 3y = 4x

 

take first equation and fint the x --> x = 3 - 2y

 

then substitute in the other equation --> - 3 - 3y = 12 - 8y

 

solve --> 5y = 15 --> y = 3

 

substitute in first equation --> 2x = -6 --> x = -3

 

 

 

and that's done

i like being awkwared

lol, this is pretty easy